[解法(솔루션) ]확률과입문 a fisrt course in probability 7판
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작성일 20-05-26 19:29
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Download : 확률의입문솔루션.pdf
11! = 34,650
that order, we see by the generalized basic principle that there are 2 ⋅ 1 ⋅ 2 ⋅ 1 = 4 possibilities.
출판사 & 저자 : sheldon ross
2. 64 = 1296
(b) 26 ⋅ 25 ⋅ 10 ⋅ 9 ⋅ 8 ⋅ 7 ⋅ 6 = 19,656,000
represents which of that wife’s 7 sacks contain the kitten; k represents which of the 7 cats in
26 ⋅ 26 ⋅ 10 ⋅ 10 ⋅ 10 ⋅ 10 ⋅ 10 = 67,600,000
(d) 6 ⋅ 3 ⋅ 2 ⋅ 2 ⋅ 1 ⋅ 1 = 72
(d) 4!24 = 384
3. An assignment is a sequence i1, …, i20 where ij is the job to which person j is assigned. Since
(12)! = 27,720
7! = 1260
(b)
(b) 2 ⋅ 3! ⋅ 3! = 72
7. (a) 6! = 720
(c) 4!3! = 144
(b) 2 ⋅ 7! = 10,080
레포트 > 공학,기술계열
2!2!
title(제목) : 확률과 입문 a fisrt course in probability 7판
Download : 확률의입문솔루션.pdf( 19 )
numbers 1, …, 20 and so there are 20! different possible assignments.
(d)
Problems
6. Each kitten can be identified by a code number i, j, k, l where each of i, j, k, l is any of the
8. (a) 5! = 120
7! = 1260
sack j of wife i is the mother of the kitten; and l represents the number of the kitten of cat k in
(c) 5!4! = 2,880
(c)
5. There were 8 ⋅ 2 ⋅ 9 = 144 possible codes. There were 1 ⋅ 2 ⋅ 9 = 18 that started with a 4.
확률,솔루션,입문,7판,probability
sack j of wife i. By the generalized principle there are thus 7 ⋅ 7 ⋅ 7 ⋅ 7 = 2401 kittens
순서
다. 내용을 잘 읽어보시고 확실한 자료라고 생각되시면 다운을 받아주시면 됩니다. 4. There are 4! possible arrangements. By assigning instruments to Jay, Jack, John and Jim, in
9.
10. (a) 8! = 40,320
only one person can be assigned to a job, it follows that the sequence is a permutation of the
6!4!
설명
4!4!2!
1. (a) By the generalized basic principle of counting there are
[解法(솔루션) ]확률과입문 a fisrt course in probability 7판
2!2!
잘못된 資料가 있을시 환불요청 하시면 환불을 받으실수 있습니다.
numbers from 1 to 7. The number i represents which wife is carrying the kitten, j then
제목 : 확률과 입문 a fisrt course in probability 7판 출판사 & 저자 : sheldon ross 잘못된 자료가 있을시 환불요청 하시면 환불을 받으실수 있습니다. 내용을 잘 읽어보시고 확실한 資料라고 생각되시면 다운을 받아주시면 됩니다.
